IEC 60909-0 / IEC 60947-210 min read

Breaker Duty Check: Icu, Icm and Icw for a 2.5 MVA Main LV Switchboard

Part 6 of the short-circuit series. A 65 kA board looks right until the motor contribution is added: 68.8 kA r.m.s. and 175 kA peak. How to check breaking, making and short-time ratings.

Scenario

Supply500 MVA, 11 kV grid → 2.5 MVA, 11/0.4 kV Dyn transformer, uk = 6.25 %, Pk = 22 kW
Motors1,000 kW of running motors on the main LV switchboard
CandidateSwitchboard and ACB rated Icu = 65 kA
Settingstmin = 0.1 s, Ith duration tk = 1 s

Step-by-step calculation

Step 1: Initial symmetrical current

From the transformer 57.75 kA and from the motors 11.38 kA.

Step 2: Breaking capacity (Icu)

Ik″ must not exceed the breaker's rated ultimate short-circuit breaking capacity. With the motor contribution kept in full, Ib = Ik″.

Step 3: Peak current and making capacity (Icm)

κ = 1.02 + 0.98 e^(−3R/X); several sources → κ(b) = 1.15 κ ≤ 1.8 (LV); ip = κ √2 Ik″
R/X = 0.182 → κ = 1.588; 1.15 × 1.588 = 1.83 → limited to 1.8; ip = 1.8 × 1.414 × 68.81
ip = 175.2 kA

IEC 60947-2 Table 2: for Icu above 50 kA the minimum making capacity is Icm = 2.2 × Icu. A 65 kA breaker gives 143 kA < 175 kA; an 85 kA breaker gives 187 kA ≥ 175 kA.

Step 4: Short-time withstand (Icw) for selectivity

Ith = Ik″ × √(m + n)
Ith (1 s) = 69.5 kA — the ACB needs Icw ≥ 69.5 kA for 1 s if it uses a short-time delay

Result summary

CheckRequirementActualStatus
Icu 65 kA vs Ik″≥ 68.81 kA65 kA✗ FAIL
Icu 85 kA vs Ik″≥ 68.81 kA85 kA✓ PASS
Icm = 2.2 × 85 kA vs ip≥ 175.2 kA187 kA✓ PASS
Icw (1 s)≥ 69.5 kASelect ACB with Icw ≥ 70 kA, 1 s✓ PASS
The main switchboard needs at least 85 kA breaking capacity (Ik″ = 68.8 kA), a making capacity of at least 175 kA peak and, if short-time delays are used for selectivity, a 1 s withstand of about 70 kA. The 65 kA proposal fails on both breaking and making capacity.

Key insight: Three different ratings protect against three different stresses: Icu for interrupting, Icm for the first asymmetrical peak, and Icw for carrying the fault while a downstream device clears it.

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Frequently asked questions

Why does the calculator use method B for κ?

When several sources feed the fault, IEC 60909 method B (1.15 κ) is a safe single-value approach. For purely radial sources the standard also allows summing the partial peak currents, which can give a somewhat lower ip.

Is Ics important?

Ics is the service breaking capacity, after which the breaker remains usable. Many specifications require Ics = 100 % Icu for main breakers.

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