IEEE 1584-2018 / IEC 6090910 min read

Arc Flash Study for a Small Network: Energy, Boundary and PPE at Every Bus

Part 5 of the arc flash series. An 11 kV board, a 0.4 kV LV board and an MCC studied together. The LV board is the worst point because its incomer faults are cleared by the 11 kV relay.

Scenario

Network250 MVA grid + 2.5 MVA generator at 11 kV → 1.6 MVA, 6 % transformer → 0.4 kV LV board → 50 m cable → MCC with a 160 kW motor
11 kV board15 kV switchgear, clearing 300 ms
LV boardLV switchgear, cleared by the transformer's 11 kV relay (IEC SI, pickup 100 A, TMS 0.15, breaker 50 ms)
MCCShallow LV MCC, cleared by the feeder breaker in 100 ms
BasisFault currents at nominal voltage (c = 1), maximum and minimum cases

Step-by-step calculation

Step 1: Fault currents from IEC 60909

Step 2: Results at each bus

BusClearingE (cal/cm²)BoundaryIndicative PPE
11 kV switchboard300 ms4.702.18 mCategory 2
0.4 kV LV board526 ms21.23.68 mCategory 3
MCC100 ms2.540.73 mCategory 1

Step 3: Why the LV board is worst

A fault on the LV board's incoming terminals is upstream of the LV incomer breaker, so only the 11 kV relay can clear it. Seen from 11 kV the current is small (about 1.4 kA), so the IDMT relay takes over half a second.

Step 4: Mitigation

The calculator reports that 199 ms would bring the LV board to Category 2. A maintenance setting on the 11 kV relay clearing in 50 ms gives 2.01 cal/cm².

Step 5: Labels

Each bus gets a label with the incident energy (or PPE category), the arc-flash boundary, working distance, voltage and the limited and restricted approach boundaries, as NFPA 70E 130.5(H) requires.

Result summary

CheckRequirementActualStatus
11 kV switchboard≤ 8 cal/cm²4.70 cal/cm²✓ PASS
0.4 kV LV board≤ 8 cal/cm²21.2 cal/cm²✗ FAIL
MCC≤ 8 cal/cm²2.54 cal/cm²✓ PASS
The study gives 4.7 cal/cm² at the 11 kV board, 21.2 at the LV board and 2.5 at the MCC. The LV board needs mitigation: a maintenance setting on the 11 kV relay reduces it to 2.0 cal/cm².

Key insight: The worst location is usually the main LV board fed directly from a transformer, because its incomer terminals rely on HV protection that cannot be fast without losing selectivity.

Try it with your own numbers

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Frequently asked questions

Why is nominal voltage (c = 1) used for arc flash?

IEEE 1584 works from the available bolted fault current at the operating voltage; the IEC 60909 maximum factor would overstate it. The minimum case is also studied because lower current can mean slower clearing.

Is this the default network in the calculator?

Yes. Open the Arc Flash Study calculator to see the same network and change any value.

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