IEC 60255-151 / IEEE C57.10910 min read

Transformer HV Relay Settings: Clearing Inrush and Staying Below the Damage Curve

Part 3 of the protection series. Setting the 11 kV relay of a 1.6 MVA transformer: above inrush, below the IEEE C57.109 damage curve, and with an instantaneous element that ignores LV faults.

Scenario

Transformer1.6 MVA, 11/0.4 kV, Dyn, uk 6 % — HV full-load current 84.0 A
RelayIEC Standard Inverse, pickup 100 A (1.19 × FLC), TMS 0.10
Maximum LV three-phase fault37.4 kA at 0.4 kV → 1,360 A seen at 11 kV (16.2 × FLC)
Inrush (assumed)8 × FLC for 0.1 s = 672 A (12 × FLC = 1,008 A for comparison)

Step-by-step calculation

Step 1: Inrush: the relay must not trip

t = 0.14 × TMS / ((I/Is)^0.02 − 1)
At 672 A: M = 6.72 → t = 0.36 s; at 1,008 A: t = 0.30 s
Both well above the 0.1 s inrush duration — no trip

Step 2: Damage curve (thermal part, IEEE C57.109 category II)

t = 1250 / I² (I in per unit of FLC)
At 16.2 pu: t = 1250/16.2² = 4.76 s; relay at 1,360 A: 0.26 s
Relay clears far below the damage curve

Step 3: Instantaneous element

Set above the maximum LV fault seen from HV, so the HV relay does not trip for faults the LV breakers should clear, and above inrush.

Step 4: LV earth faults look smaller from HV

With a Dyn transformer an LV phase-to-earth fault appears in only two HV lines, at 1/√3 of the ratio-transformed value.

Result summary

CheckRequirementActualStatus
No trip on inrusht > 0.1 s at 672 A0.36 s✓ PASS
Below damage curve at max through-faultt < 4.76 s0.26 s✓ PASS
Instantaneous above LV fault> 1,360 A1,800 A✓ PASS
Pickup 100 A, TMS 0.10 (IEC SI) and instantaneous 1,800 A protect the transformer: the relay rides through inrush, clears through-faults far below the damage curve, and the instantaneous element only sees HV-side faults. Part 4 checks grading with the LV incomer, which needs a slightly higher TMS.

Key insight: A transformer HV relay sits between three limits: inrush (lower bound in time), the damage curve (upper bound), and selectivity with the LV incomer. The instantaneous setting must stay above the largest LV fault seen from HV.

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Frequently asked questions

What inrush multiple should be used?

Typically 8–12 × FLC for 0.1 s for distribution transformers; use the manufacturer's value when available.

Why only the thermal part of the damage curve?

For category II–IV transformers IEEE C57.109 adds a mechanical-duty curve for frequent faults; the calculator shows the thermal part and notes the limit.

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